74. 搜索二维矩阵
2024/3/16小于 1 分钟
74. 搜索二维矩阵
中等解法思路: 二维矩阵的二分查找,mid = (left + right) // 2; x = matrix[mid // n][mid % n]
class Solution:
def searchMatrix(self, matrix: List[List[int]], target: int) -> bool:
m, n = len(matrix), len(matrix[0])
left, right = 0, m * n - 1
while left <= right:
mid = (left + right) // 2
mid_m = mid // n
mid_n = mid % n
if matrix[mid_m][mid_n] == target:
return True
elif matrix[mid_m][mid_n] > target:
right = mid - 1
else:
left = mid + 1
return False