145_二叉树的后序遍历
小于 1 分钟
145_二叉树的后序遍历
简单class Solution {
    public List<Integer> postorderTraversal(TreeNode root) {
        ArrayList<Integer> res = new ArrayList<>();
        if(root == null){
            return res;
        }
        inorder(root,res);
        return res;
    }
    public void inorder(TreeNode root,ArrayList<Integer> res){
        if(root.left != null) {
            inorder(root.left, res);
        }
        if(root.right != null){
            inorder(root.right,res);
        }
        res.add(root.val);
    }
}
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